Find an equation of the tangent line to the curve y=10^(x) at the point (1,10)

2 answers

The equation of the tangent line is y = 10(x - 1) + 10.
I just know that the bot will screw up this one for sure

y = 10^x
dy/dx = ln10 (10^x)
at (1,10) , dy/dx = 10ln10

so the equation of the tangent at (1,10)
y - 10 = 10ln10(x - 1)
or
y = 10ln10 x - 10ln10 + 10
Similar Questions
  1. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 1 answer
  2. Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 .a. Show that dy/dx= (4x-2xy)/(x^2+y^2+1) b. Write an equation of each
    1. answers icon 3 answers
  3. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 0 answers
  4. original curve: 2y^3+6(x^2)y-12x^2+6y=1dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
    1. answers icon 3 answers
more similar questions