Find an equation of the tangent line to the curve y=10^(x) at the point (1,10)
2 answers
The equation of the tangent line is y = 10(x - 1) + 10.
I just know that the bot will screw up this one for sure
y = 10^x
dy/dx = ln10 (10^x)
at (1,10) , dy/dx = 10ln10
so the equation of the tangent at (1,10)
y - 10 = 10ln10(x - 1)
or
y = 10ln10 x - 10ln10 + 10
y = 10^x
dy/dx = ln10 (10^x)
at (1,10) , dy/dx = 10ln10
so the equation of the tangent at (1,10)
y - 10 = 10ln10(x - 1)
or
y = 10ln10 x - 10ln10 + 10