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Find an equation of the tangent line to the curve at (8,0). y=ln(x^2 -8x +1)

1 answer

dy/dx = (2x - 8)/(x^2 - 8x + 1)
at (8,0) , dy/dx = (16-8)/(64-64+1) = 8

so for y = mx + b
y = 8x + b
at (8,0),
0 = 64 + b, ---> b = -64

equation: y = 8x - 64
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