(y-y1)=m(x-x1) you are given m, and x1=-7 and y1=-3.
Go for it.
Find an equation in point-slope form for a line having the slope of m=1/6 and containing the point (-7,-3).
3 answers
(Y1-y)/(X1-x) = 1/6
(-3-y)/(-7-x) = 1/6
-x-7 = -18-6y
18+6y = x+7
6y = x - 11
(-3-y)/(-7-x) = 1/6
-x-7 = -18-6y
18+6y = x+7
6y = x - 11
Thank you