Find an equation for the tangent to the curve y=1+ (sqrt2)(csc(X)) + cot(X).

Question

I just learned, though my teacher wasn't super good with explaining, derivatives for trig functions but they still aren't making too much sense. Could you please give me a step by step solution for this example please?

Thank you so much!

Answer 1

so you need the derivative of this thing.

y = 1 + (cscx + cotx)^1/2

dy/dx = (1/2)(cscx + cotx)^(-1/2) ( -cscx cotx - csc^2 x)
I was going to simplify this, but then realized that you were missing some information.
e.g. what point does the tangent pass through ?

I am also puzzled by the "sqrt2" , I read it as the square root

Answer 2

Yes it is square root. I think I figured out the question now. Thanks!!