f(x)=x+4/x
f'(x)=1-4/x^2
f'(2)=1-1=0
Equation of tangent line:
y=0(x-2)+4, or
y=4
Find an equation for the tangent line of the function y=x+(4/x) at the point (2, 4).
The equation of the tangent line is .
You may enter the equation in any form.
1 answer