First we need the slope:
slope = (-3-0)/(-4 + 2) = 3/2
since Q(-2,0) lies on it
in y = mx + b
0 = (3/2)(-2) + b
b = 3
y = (3/2)x + 3
Find an equation for the line with the given propertiesExpress the equation in slope-intercept form. Containing the points P = (-4,-3) and Q= (-2,0)
2 answers
the slope is (0+3)/(-2+4) = 3/2
so y = 3/2 x + b
Now use either point to determine b
so y = 3/2 x + b
Now use either point to determine b