Find an equation for the line satisfying the given conditions.Through (3, 3) and parallel to 4x - 3y = 6.

y=?

3 answers

the slope of 4x-3y=6 is 4/3
So, you want a line with slop -3/4

(y-3)/(x-3) = -3/4

rearrange that as you will
4/3x -1
Since the new line is parallel to 4x-3y = 6, it will differ only in the constant

let new line be 4x-3y = k
but (3,3) lies on it, so
12 - 9 = k - 3

new equation: 4x - 3y = 3
or
3y = 4x - 3
y = (4/3)x - 1
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