2 x^2 - 4 x + c = 0
for real solution
sqrt (4^2 - 4*2*c) must be real
so
16 - 8 c must be positive
so
8 (2-c) must be positive
so
c <= 2
Find all values of 𝑐, so that the solutions of the following equation are real numbers
2x2 − 4𝑥 + 𝑐 = 0
1 answer