g'=3x^2-4=0
x= +- sqrt (3/4)
g''=6x at +sqrt (3/4) it is +, and at - sqrt (3/4) it is negative.
find all the local maxima and minima (the y-values) and the values of x where they occur.
g(x)=x^3-4x+1
8 answers
so what is the local maxima and minima
Well, this means you don't know any calculus.
So graph it, and read the values. Do it on your calculator.
So graph it, and read the values. Do it on your calculator.
do you have an idea how i can find it
you called it pre-calc so I guess we can't use Calculus, too bad.
Do you have use of a programmable calculator?
Some classes now use those to solve your kind of question.
You could make a table of values, graph it, then by trial and error and a scientific calculator find the largest and smallest y values you can find.
hint: the min is just a little to the left of (1,-2), and the max is around (-1,4)
Do you have use of a programmable calculator?
Some classes now use those to solve your kind of question.
You could make a table of values, graph it, then by trial and error and a scientific calculator find the largest and smallest y values you can find.
hint: the min is just a little to the left of (1,-2), and the max is around (-1,4)
yes i do the class i am in is pre calc
is the minima x=1.15 y= -2.07
maxima x=-1.15 y=4.07
maxima x=-1.15 y=4.07
Yes, you are correct to one decimal accuracy.