Asked by Paige

Find a Cartesian equation for the polar curve y = 5tan(theta)sec(theta). I think I got it but I just wanted to double check. Thanks in advance!
Answered by MathMate
Would you like to post your answer if you just wanted to check?
Answered by Mgraph
y=... or r=...?
Answered by MathMate
It would be in the form:
x=f(θ),
y=g(θ)
where f and g are functions of θ.
Answered by Mgraph
Read the terms of your problem!
Answered by Mgraph
If r=tan(theta)sec(theta)
then r(cos(theta)^2)=sin(theta)
(r*cos(theta))^2=r*sin(theta)
x^2 = y
Answered by Paige
I am sorry, it is r = 5tan(theta)sec(theta)
Answered by Paige
Mggraph: but (r*cos(theta))^2 is not x^2, is it? I thought rcos(theta) = x^2

This is what I got:

1 = 5y/[(x^2)(square root of(x^2 + y^2))]
Answered by Mgraph
Then all right sides multiply by 5:
x^2=5y or
y=0.2x^2
Answered by Paige
Aha I got it! Thanks so much! :)
Answered by Víctor
if I've this equation: r=sec theta tan theta. How is?
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