Find a Cartesian equation for the polar curve y = 5tan(theta)sec(theta). I think I got it but I just wanted to double check. Thanks in advance!

Answer 1

Would you like to post your answer if you just wanted to check?

Answer 2

y=... or r=...?

Answer 3

It would be in the form:
x=f(θ),
y=g(θ)
where f and g are functions of θ.

Answer 4

Read the terms of your problem!

Answer 5

If r=tan(theta)sec(theta)
then r(cos(theta)^2)=sin(theta)
(r*cos(theta))^2=r*sin(theta)
x^2 = y

Answer 6

I am sorry, it is r = 5tan(theta)sec(theta)

Answer 7

Mggraph: but (r*cos(theta))^2 is not x^2, is it? I thought rcos(theta) = x^2

This is what I got:

1 = 5y/[(x^2)(square root of(x^2 + y^2))]

Answer 8

Then all right sides multiply by 5:
x^2=5y or
y=0.2x^2

Answer 9

Aha I got it! Thanks so much! :)

Answer 10

if I've this equation: r=sec theta tan theta. How is?