Question
I'm extremely confused on what to do in part a of this question.
Consider the curve given by x=3sin(theta), y=1+2cos(theta), 0<=theta<=3pi/2
(a) Eliminate the parameter and find a Cartesian (Rectangular) equation for the curve.
Consider the curve given by x=3sin(theta), y=1+2cos(theta), 0<=theta<=3pi/2
(a) Eliminate the parameter and find a Cartesian (Rectangular) equation for the curve.
Answers
Your basic replacement identities are:
r^2 = x^2 + y^2
x = rcosØ and y = rsinØ or cosØ = x/r and sinØ = y/r
so you have:
x =3sinØ ---> sinØ = x/3
y = 1+2cosØ
cosØ = (y-1)/2
but we know sin^2 Ø + cos^2 Ø = 1
x^2/9 + (y-1)^2 /4 = 1
looks like an ellipse to me
r^2 = x^2 + y^2
x = rcosØ and y = rsinØ or cosØ = x/r and sinØ = y/r
so you have:
x =3sinØ ---> sinØ = x/3
y = 1+2cosØ
cosØ = (y-1)/2
but we know sin^2 Ø + cos^2 Ø = 1
x^2/9 + (y-1)^2 /4 = 1
looks like an ellipse to me
Related Questions
A switch on the part of the public from large cars to smaller cars should cause the demand curve for...
(a) Find dy/dx given that x^2+y^2-4x+7y=15.
(b) Under what conditions on x and/or y is the tangen...
Consider the closed curve in the day plane:
2x^2-2xy+y^3=14
a) show that dy/dx=2y-4x/3y^2-2x (I...
This question has two parts. Answer Part A, and then answer
Part B.
Part A
What does the phrase h...