To solve \(0.078 - (5.2 \times 10^{-3})\), we start by converting \(0.078\) into scientific notation.
We can express \(0.078\) as:
\[ 0.078 = 7.8 \times 10^{-2} \]
Now, we need to convert \(5.2 \times 10^{-3}\) into the same exponent as \(7.8 \times 10^{-2}\). We do this by expressing \(5.2 \times 10^{-3}\) with an exponent of \(-2\):
\[ 5.2 \times 10^{-3} = 0.052 \times 10^{-2} \]
Now we perform the subtraction:
\[ 7.8 \times 10^{-2} - 0.052 \times 10^{-2} = (7.8 - 0.052) \times 10^{-2} \]
Calculating \(7.8 - 0.052\):
\[ 7.8 - 0.052 = 7.748 \]
Thus:
\[ 7.748 \times 10^{-2} \]
Now, to express this in standard scientific notation, we should adjust \(7.748\) to be between 1 and 10. We rewrite it:
\[ 7.748 = 0.7748 \times 10^{1} \]
Combining this with the original power of ten, we get:
\[ 0.7748 \times 10^{1} \times 10^{-2} = 0.7748 \times 10^{-1} \]
So, the answer in scientific notation is:
\[ 7.748 \times 10^{-2} = 0.7748 \times 10^{-1} \quad (if expressed in standard scientific notation format) \]
However, keeping the original phrasing:
\[ \boxed{7.748 \times 10^{-2}} \]
Thus, you would write as \(7.748 , \text{x} , 10^{-2}\) if you follow the original prompt strictly using that notation.