Fe^+2 ==> Fe^+3 + e
Cr2O7^2- +6e + 14H^+ ==>2Cr^3+ + 7H2O
You finish. Multiply equation 1 by 6 and equation 2 by 1, then add the two.
Fe2+(aq) + Cr2O7 2- (aq) →Fe3+(aq) + Cr3+(aq)
Balance the equation by using oxidation and reduction half reactions. What is smallest possible integer coefficient of Cr3+ in the combined balanced equation?
2 answers
Answer pats hair bhaag
1 answer