Asked by Samuel

What is the oxidation half reaction for the following equation: Cr2O7^-2 +Fe+2 - - > Cr^+3 + Fe^+3

Cr^+3 - - > Cr2O7^-2
Fe^+2 - - > Fe^+3
Fe^+3 - - > Fe^+2
Cr2O7^-2 - -> Cr^+3***
Answered by DrBob222
Did you leave off the electrons? What you have check is the reduction reaction but that isn't right because the electrons have been omitted.
Oxidation is the loss of eletrons.
Fe^2+ ==> Fe^3+ + e is the oxidation half reaction.
Also note that neither A nor D are balanced. They don't have the right number of Cr atoms, nor O atoms, and the charges don't balance.
Answered by DrBob222
Something is wrong with the Zn/Cu question above. You have answered it correctly but the computer won't show my answer when I try to post it.
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