Farmer Brown has cows and ducks. There is a total of 148 "feet." Figure out how many of each Farmer Brown has. Could someone help me with this question.

Answer 1

Cows have 4 legs, chickens have 2 legs, so
cows ---x , chickens ---- y
4x + 2y = 148
2x + y = 74
y = 74 - 2x

pick any x from 0 to 37, to get the y
e.g. if he has 20 cows, then he has 74-40 or 34 chickens
check: 20 cows have 80 legs, 32 chickens have 68 legs. 80+68 = 148
e.g. if he has 5 cows, then he has 74-10 or 64 chickens
check: 5 cows have 20 legs, 64 chickens have 128 legs. 20+128 = 148

Was there more information?

Answer 2

It not Chicken it ducks and it feet not legs were did you get 74-2x from

Answer 3

Wow,
replace the word chicken with ducks, and the word legs with feet.
Same question!

Where does the 74-2x come from?
Did you look at the algebra in my solution?

Answer 4

All it said was there were 148 "feet" that was the total it say to figure out how many of each farmer Brown has.

Answer 5

Did you not understand that there cannot be a unique solution if that is the only information you were given?
Since the question says that the farmer "has cows and ducks" we can assume that he must have at least one of each type.
so x could be 1,2,3,...., 36
for a possible 36 different answers.

I even gave you two possible solutions.