10y²+21y-10=0
10y²+25y-4y-10=0
(10y²+25)-(4y+10)=0
5y(2y+5)-2(2y+5)=0
(5y-2)(2y+5)=0
5y-2=0 or 2y+5=0
Y=2/5 or y=-5/2
Factories the following quadratic equations 10Y2 + 21Y-10
3 answers
typo?
(10y²+25)-(4y+10)=0
or
(10y²+25y)-(4y+10)=0
(10y²+25)-(4y+10)=0
or
(10y²+25y)-(4y+10)=0
Thanks sir yes it was a typo