Asked by maria
factor the following expression? Do not leave negative exponents.
21(x−8)^1/4 (x^2+7)^2/3 +14(x−8)^5/4(x^2+7)^−1/3
21(x−8)^1/4 (x^2+7)^2/3 +14(x−8)^5/4(x^2+7)^−1/3
Answers
Answered by
oobleck
You can see there is (x-8) and (x^2+27) in both terms.
You probably want to factor out the lowest power of those factors.
also, 21 and 14 are both multiples of 7, so
21(x−8)^1/4 (x^2+7)^2/3 +14(x−8)^5/4(x^2+7)^−1/3
7(x-8)^1/4 (x^2+7)^-1/3 (3(x^2+7) + 2(x-8))
7(x-8)^1/4 / (x^2+7)^1/3 (3x^2+21+2x-16)
7(x-8)^1/4 (3x^2+2x-5)
-------------------------------
(x^2+7)^1/3
or
7(x-8)^1/4 (x-1)(3x+5)
-------------------------------
(x^2+7)^1/3
You probably want to factor out the lowest power of those factors.
also, 21 and 14 are both multiples of 7, so
21(x−8)^1/4 (x^2+7)^2/3 +14(x−8)^5/4(x^2+7)^−1/3
7(x-8)^1/4 (x^2+7)^-1/3 (3(x^2+7) + 2(x-8))
7(x-8)^1/4 / (x^2+7)^1/3 (3x^2+21+2x-16)
7(x-8)^1/4 (3x^2+2x-5)
-------------------------------
(x^2+7)^1/3
or
7(x-8)^1/4 (x-1)(3x+5)
-------------------------------
(x^2+7)^1/3
Answered by
oobleck
oops. 21-16 = 5, not -5
7(x-8)^1/4 (3x^2+2x+5)
-------------------------------
(x^2+7)^1/3
7(x-8)^1/4 (3x^2+2x+5)
-------------------------------
(x^2+7)^1/3
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