Asked by Saira
factor the equation: -6x^2+15x+36
please show me the steps in answering this problem.
thanksss..)
Answers
Answered by
Joe
What are the factors of 1000
Answered by
MathMate
-6x^2+15x+36 is an expression. An equation has an equal sign.
First take out common factors
-3(2x²-5x-12)
Now concentrate on the part in parentheses.
Make a table of possible combinations of factors that multiply to the constant term (-12) and put them in the first two columns. For example, -1 and 12.
Multiply the first column by the coefficient of the term in x² (2) and add to the second column. Put the result in the third column (-1*2 + 12 = 10):
-1 12 10
Compare the third column with the coefficient of the term in x, i.e. -5. If they compare, you have found the factors: (x+A)(2x+B) where A and B are the numbers in the first and second columns.
Let's continue:
A B 2*A+B
#-1 12
12 -1 12*2+(-1)=23
#2 -6
4 -3 2*4-3=5 (Found, but wrong sign)
-4 3 2*(-4)+3=-5 (switched sign)
# Since we have already taken out all common factors, we do not have to check cases where B is even, which makes 2x+2k (k=integer).
The intermediate answer is (x-4)(2x+3).
Check by expanding: 2x²-8x+3x-12=x²-5x-12
The final answer is -3(x-4)(2x+3).
First take out common factors
-3(2x²-5x-12)
Now concentrate on the part in parentheses.
Make a table of possible combinations of factors that multiply to the constant term (-12) and put them in the first two columns. For example, -1 and 12.
Multiply the first column by the coefficient of the term in x² (2) and add to the second column. Put the result in the third column (-1*2 + 12 = 10):
-1 12 10
Compare the third column with the coefficient of the term in x, i.e. -5. If they compare, you have found the factors: (x+A)(2x+B) where A and B are the numbers in the first and second columns.
Let's continue:
A B 2*A+B
#-1 12
12 -1 12*2+(-1)=23
#2 -6
4 -3 2*4-3=5 (Found, but wrong sign)
-4 3 2*(-4)+3=-5 (switched sign)
# Since we have already taken out all common factors, we do not have to check cases where B is even, which makes 2x+2k (k=integer).
The intermediate answer is (x-4)(2x+3).
Check by expanding: 2x²-8x+3x-12=x²-5x-12
The final answer is -3(x-4)(2x+3).
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