Factor completely.

36a^3b^2+66a^2b^3-210ab^4

Is this correct?
6ab^2(6a^2+11ab-35b^2)

2 answers

Yes, it is correct as far as it goes. But
(6a^2+11ab-35b^2)
is also factorable into
(3a - _b)(2a + _b). See if you can figure out the missing numbers
So would it be 6ab^2(3a-5b)(2a+7b)?