Parentheses are required. As it is, it will be interpreted as:
f(x)=(12x/sin(x))+cos(x)
For f(x)=12x/(sin(x)+cos(x))
f(π)
= 12π/(sin(π)+cos(π)
= 12π/(0+(-1))
= -12π
f(x)=12x/sinx+cosx
find f(-pie)
6 answers
the computer says its not the answer incorrect it says
The required problem was
f(-π)
= 12(-π)/(0+(-1))
= 12π
Sorry for the oversight. Hope you still have "lives" left.
Do check my answer and agree with it before going to the computer!
f(-π)
= 12(-π)/(0+(-1))
= 12π
Sorry for the oversight. Hope you still have "lives" left.
Do check my answer and agree with it before going to the computer!
i have unlimited trys so it don't matter but 12pi not the answer either
Have you checked my assumptions?
I worked with
f(x)=12x/(sinx+cosx)
and not
f(x)= (12x/sinx) + cosx
as you posted.
Check also if there is any typo on the question.
If everything is correct, then
f(-π)=12π, since sin(-π)=0, cos(-π)=-1.
Check also how you entered π in your answer. Do not enter 3.14 or 3.1416. There is a special "button" to enter the symbol π.
I worked with
f(x)=12x/(sinx+cosx)
and not
f(x)= (12x/sinx) + cosx
as you posted.
Check also if there is any typo on the question.
If everything is correct, then
f(-π)=12π, since sin(-π)=0, cos(-π)=-1.
Check also how you entered π in your answer. Do not enter 3.14 or 3.1416. There is a special "button" to enter the symbol π.
yeah its 12x/(sinx+cosx) but in my problem there is no ( ) but yeah its the same thing but what would the equation be to plug in (-pie)
1 answer