f(x)=12x/(sinx+cosx)

Question

find f'(-pie)
need some help!

Answer 1

use the quotient rule:
http://www.allaboutcircuits.com/vol_5/chpt_6/6.html

here are the derivatives of some elementary functions:
http://www.karlscalculus.org/divrules.html

Answer 2

Did you find f'(x) first?

I just read your earlier post and you said you plugged -pi into
12x/(sinx+cosx) .

You have to find f' first, then plug in (-pi).

The derivative, f' is,

(12(x sin x + sin x - x cos x + cos x)/
(sin x + cos x)^2

Then you plug in (-pi)

You realize that the derivative can be in various forms depending on how you factor it.

I also checked my answer in an online calculator and it said both answers are correct, the derivative and f'(-pi).

f'(-pi) = -12 - 12pi
or, 12(-1 - pi)

Where are you checking your answer?

Answer 3

Daniel, thought I would jump in here again.

The answer that Helper gave you several times is correct, I had the same result as did MathMate.

The problem appears to be the way you are expected to enter that answer in an answer window on some kind of webpage.

without doubt the answer is
-12 - 12π, or
-(12+π) or
-12π-12 or
-12(1+π) or
etc

If your computer does not accept any of these variations, then it is the fault of their program.

Answer 4

Thank you so much Reiny.