Express your answer in scientific notation.%0D%0A%0D%0A(1.87 × 109) × (6.7 × 106)%0D%0A(%0D%0A1.87%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A9%0D%0A)%0D%0A %0D%0A %0D%0A×%0D%0A %0D%0A %0D%0A(%0D%0A6.7%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A6%0D%0A)%0D%0A %0D%0A%0D%0AShow your work.%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A12.529 × 1036%0D%0A12.529%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A36%0D%0A12.529 × 1036%0D%0A12.529%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A36%0D%0A%0D%0A8.57 × 1016%0D%0A8.57%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A16%0D%0A8.57 × 1016%0D%0A8.57%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A16%0D%0A%0D%0A1.2529 × 1016%0D%0A1.2529%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A16%0D%0A1.2529 × 1016%0D%0A1.2529%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A16%0D%0A%0D%0A12.529 × 1015

3 answers

To solve the expression \( (1.87 \times 10^9) \times (6.7 \times 10^6) \), we can follow these steps:

  1. Multiply the coefficients: \[ 1.87 \times 6.7 \] Using a calculator, this gives: \[ 1.87 \times 6.7 = 12.529 \]

  2. Add the exponents: The exponents in our bases of 10 are 9 and 6: \[ 10^9 \times 10^6 = 10^{9+6} = 10^{15} \]

  3. Combine the results: Now we combine the coefficient with the power of ten: \[ 12.529 \times 10^{15} \]

  4. Express in scientific notation: Scientific notation requires that the coefficient is between 1 and 10. Since \( 12.529 \) is not in this range, we can rewrite it: \[ 12.529 = 1.2529 \times 10^1 \] Therefore, \[ 12.529 \times 10^{15} = 1.2529 \times 10^1 \times 10^{15} = 1.2529 \times 10^{16} \]

Thus, the final answer in scientific notation is: \[ \boxed{1.2529 \times 10^{16}} \]

no words

Sure! Here’s the solution in a straightforward format:

\[ (1.87 \times 10^9) \times (6.7 \times 10^6) \]

  1. Multiply coefficients: \[ 1.87 \times 6.7 = 12.529 \]

  2. Add exponents: \[ 10^9 \times 10^6 = 10^{15} \]

  3. Combine: \[ 12.529 \times 10^{15} \]

  4. Convert to scientific notation: \[ 12.529 = 1.2529 \times 10^1 \] \[ 1.2529 \times 10^{1} \times 10^{15} = 1.2529 \times 10^{16} \]

Final answer: \[ \boxed{1.2529 \times 10^{16}} \]