Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Explain how to factor the following trinomials forms: x2 + bx + c and ax2 + bx + c. Is there more than one way to factor this?...Asked by Austin
Explain how to factor the following trinomials forms: x2 + bx + c and ax2 + bx + c. Is there more than one way to factor this? Show your answer using both words and mathematical notation.
Answers
Answered by
Henry
Factor x^2 + 5x + 6
C = 6 = 1*6 = 2*3.
Select the pair of factors whose sum equals B which is 5.
We select 2 and 3, because their sum = 5.
Solution: (x+2)(x+3).
The solution can be checked by performing the multiplication and
combining like-terms.
Factor 2x^2 + 11x + 12.
This and the previous example can be done by trial and error, but the process can be tedious and very frustrating.
We'll use the AC Method:
A*C = 2 * 12 = 24 = 3*8 = 4*3.
We select the pair of factors whose sum = B(11). Therfore, we select 3 and 8.
2x^2 + (3x+8x) + 12
Arrange the 4 terms into two factorable binomials:
(2x^2+3x) + (8x+12)
x(2x+3) + 4(2x+3)
(2x+3)(x+4).
I hope this helps.
C = 6 = 1*6 = 2*3.
Select the pair of factors whose sum equals B which is 5.
We select 2 and 3, because their sum = 5.
Solution: (x+2)(x+3).
The solution can be checked by performing the multiplication and
combining like-terms.
Factor 2x^2 + 11x + 12.
This and the previous example can be done by trial and error, but the process can be tedious and very frustrating.
We'll use the AC Method:
A*C = 2 * 12 = 24 = 3*8 = 4*3.
We select the pair of factors whose sum = B(11). Therfore, we select 3 and 8.
2x^2 + (3x+8x) + 12
Arrange the 4 terms into two factorable binomials:
(2x^2+3x) + (8x+12)
x(2x+3) + 4(2x+3)
(2x+3)(x+4).
I hope this helps.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.