Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Explain how to factor the following trinomial forms: x² + bx + c and ax² + bx + c. Is there more than one way to factor these?...Asked by Lisa
Explain how to factor the following trinomials forms: x2 + bx + c and ax2 + bx + c. Is there more than one way to factor this? Show your answer using both words and mathematical notation
Answers
Answered by
Henry
1. Factor: x^2 - 2x - 3.
C = -3 = 1*(-3) = -1*3.
Select the pair whose algebraic sum = -2(1,and-3).
(x+1)(x-3).
The above method works best when the coefficient of x^2 is 1.
2. Factor: 2x^2 + x - 6.
The AC method should be used when the
coefficient of x^2 is not 1:
A*C=2*(-6) = -12 = -1*12 = -2*6 = -3*4.
Use the pair of factors whose algebraic
sum = B(1):
2x^2 + (-3x+4x) - 6.
Arrange the 4 terms to form 2
factorable binomials:
(2x^2+4x) + (-3x-6)
Factor each binomial:
2x(x+2) + -3(x+2)
(x+2)(2x-3).
These 2 methods take all of the guess work out of factoring.
C = -3 = 1*(-3) = -1*3.
Select the pair whose algebraic sum = -2(1,and-3).
(x+1)(x-3).
The above method works best when the coefficient of x^2 is 1.
2. Factor: 2x^2 + x - 6.
The AC method should be used when the
coefficient of x^2 is not 1:
A*C=2*(-6) = -12 = -1*12 = -2*6 = -3*4.
Use the pair of factors whose algebraic
sum = B(1):
2x^2 + (-3x+4x) - 6.
Arrange the 4 terms to form 2
factorable binomials:
(2x^2+4x) + (-3x-6)
Factor each binomial:
2x(x+2) + -3(x+2)
(x+2)(2x-3).
These 2 methods take all of the guess work out of factoring.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.