For the last part of log4 (y^2)
you follow the pattern of
loga (x^n)
= n loga x
so log4 (y^2)
= 2 log4 y
the first part of your solution is ok
final answer:
2 + log4 x + 2 log4 y
expand the logarithm as a sum or difference and or contant multiple of logarithms
log _4 16xy^2
thank you.. I know you do this:
log _4 16+ log _4 (x)+ log _4 (y^2)
and I know the first part = 2 and the last part you use the exponent rule =y^2log4
but the middle i don't get..thanks
2 answers
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