Expand the first 3 (three) terms of the following: (2z^3-3y^3)^6

2 answers

Please help, I don't understand how to do this
Recall the Binomial Theorem:
(a+b)^6 = a^6 + C(6,1)a^5 b + C(6,2)a^4 b^2 + ...
so plug in a=2z^3 and b = -3y^3 to get
(2z^3)^6 + 6(2z^3)^5 (-3y^3) + 15(2z^3)^4 (-3y^3)^2
64 z^18 - 576 z^15 y^3 + 2160 z^12 y^6
Similar Questions
  1. Fill in the blanks!Expand and simplify the expression: -5/7 (3x + 1/4y) + 9 (x/7 - 1/28y) 1. Use the distributive property to
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. expand [e+1/e]^4 in terms of e.express [e+1/e]^4 + [e-1/e]^4 as the sum of three terms. please help
    1. answers icon 1 answer
  3. Expand.If necessary, combine like terms. \[(x+6)(x+6)=\]
    1. answers icon 1 answer
more similar questions