Expand −5/6(9b−12)

Question

.(1 point)

Answer 1

To expand the expression \(-\frac{5}{6}(9b - 12)\), you distribute \(-\frac{5}{6}\) to both terms inside the parentheses.

Starting with the first term:

\[ -\frac{5}{6} \cdot 9b = -\frac{5 \cdot 9}{6} b = -\frac{45}{6} b \]

This can be simplified to:

\[ -\frac{45}{6} b = -\frac{15}{2} b \quad \text{(dividing numerator and denominator by 3)} \]

Now for the second term:

\[ -\frac{5}{6} \cdot (-12) = \frac{5 \cdot 12}{6} = \frac{60}{6} = 10 \]

Putting it all together, we get:

\[ -\frac{5}{6}(9b - 12) = -\frac{15}{2}b + 10 \]

So the expanded expression is:

\[ -\frac{15}{2}b + 10 \]