Expand 3/8(−8−3y)

Question

.(1 point)

Answer 1

To expand the expression \( \frac{3}{8}(-8 - 3y) \), you distribute \( \frac{3}{8} \) to both terms inside the parentheses.

1. Distributing \( \frac{3}{8} \) to \(-8\): \[ \frac{3}{8} \times -8 = -\frac{24}{8} = -3 \]

2. Distributing \( \frac{3}{8} \) to \(-3y\): \[ \frac{3}{8} \times -3y = -\frac{9y}{8} \]

Combining both results, the expanded expression is: \[ -3 - \frac{9y}{8} \]

So, the expansion of \( \frac{3}{8}(-8 - 3y) \) results in: \[ -3 - \frac{9y}{8} \]