I read that as
(4/x - (1/4)x^5 + (1/2)x^7) dx
then integral would be
4ln|x| - (1/24)x^6 + (1/16)x^8 + c, where c is a constant.
Evaluate the integral. HINT [See Example 3.] (Remember to use ln |u| where appropriate.)
(4/x - 1/4x^5 + 1/2x^7)dx
3 answers
no it is just as the denominator is one with the variable 4x^5 and 2x^7 not 1/25 raised to the 6th or 1/2 raised to the 7th
then you must put brackets around it like this ....
(4/x - 1/(4x^5) + 1/(2x^7))dx
integral would be
4ln|x| + 1/(16x^4) - 1/(12x^6) + c
(4/x - 1/(4x^5) + 1/(2x^7))dx
integral would be
4ln|x| + 1/(16x^4) - 1/(12x^6) + c
3 answers