Evaluate the expression under the given conditions.

sin (A+B); tan A= 12/5, A in quadrant 3, sin B= -3sqrt(10)/10, B in quadrant 4.

1 answer

in QIII, sin and cos are both negative.
You have a 5-12-13 triangle, so
sinA = -12/13
cosA = -5/13

in QIV, cos is positive.
You have a 3-1-√10 triangle, so
cosB = 1/√10

Now apply the addition formula

sin(A+B) = sinAcosB + cosAsinB
Similar Questions
  1. Evaluate the expression under the given conditions. (show work please)sin(A-B); tan A=12/5, A in quadrant 3, sinB=-3sqrt(10)/10,
    1. answers icon 0 answers
  2. Evaluate the expression under the given conditions.? show work please!sin(A-B); tan A=12/5, A in quadrant 3, sinB=-3sqrt(10)/10,
    1. answers icon 1 answer
  3. evaluate the expression under the given conditions.cos(θ − ϕ); cos(θ) = 5/13, θ in Quadrant IV, tan(ϕ) = − square
    1. answers icon 1 answer
  4. Evaluate the expression under the given conditions.tan(A+B); cosA=-1/7, A in quadrant 3, sinB=1/2, B in quadrant 2.
    1. answers icon 1 answer
more similar questions