Construct 2 triangles,
one in quad III for angle A with sides x=-5, y = -12 and r = 13
another in quad IV for angle B with sides x = √10 , y = 3√10 and r = 10
then sinA = -12/13, cosA = -5/13
sinB = 3√10/10 , cosB = √10/10
sin(A-B) = sinAcosB - cosAsinB
= (-12/13)(√10/10) - (-5/13)(-3√10/10)
= (-12√3 - 15√10)/130
= -27√10/130
Evaluate the expression under the given conditions.? show work please!
sin(A-B); tan A=12/5, A in quadrant 3, sinB=-3sqrt(10)/10, B in quadrant 4.
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