evaluate: integration of x^2 (square root of (1-2x^3))dx

Answer 1

Let u = 1-2x^3
du = =6 x^2 dx
Your integral is INTEGRAL u^1/2*(-du/6)
= -(1/6)*u^(3/2)/(3/2)
= -(1/9)(1-2x^3)^(3/2)

Check my math

Answer 2

thanks