Let u = 1-2x^3
du = =6 x^2 dx
Your integral is INTEGRAL u^1/2*(-du/6)
= -(1/6)*u^(3/2)/(3/2)
= -(1/9)(1-2x^3)^(3/2)
Check my math
evaluate: integration of x^2 (square root of (1-2x^3))dx
2 answers
thanks
2 answers