Asked by J
Evaluate exactly the value of the integral from negative 1 to 0 of the product of the cube of quantity 2 times x to the 5th power plus 6 times x and 5 times x to the 4th power plus 3, dx. Your work must include the use of substitution and the antiderivative.
Answers
Answered by
oobleck
why, oh why, all those words? Ever hear of actual math notation? If I read it correctly, you want
∫[-1,0] (2x^5 + 6x)^3 * (5x^4 + 3) dx
Note that if we let
u = 2x^5 + 6x
du = (10x^4+6) dx = 2(5x^4+3) dx
That means that we just have
∫[-8,0] 1/2 u^3 du dx = 1/8 u^4 [-8,0] = -512
∫[-1,0] (2x^5 + 6x)^3 * (5x^4 + 3) dx
Note that if we let
u = 2x^5 + 6x
du = (10x^4+6) dx = 2(5x^4+3) dx
That means that we just have
∫[-8,0] 1/2 u^3 du dx = 1/8 u^4 [-8,0] = -512
Answered by
Lee
Why does it all of the sudden go to -8 to 0
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