=2(1)^2(1+7)
=16
Evaluate 2y^2(x+y) when x=1 and y=7
3 answers
These are my choices ...
A . 203 B. 784 C. 105 D. 392
A . 203 B. 784 C. 105 D. 392
sorry my mistake
its
=2(7)^2(1+7)
=784
that is c
its
=2(7)^2(1+7)
=784
that is c
1 answer