f(x) = |x^3|
f(5) = |5^3| = |125| = 125
work the others in the same way, recalling that
|x| = x if x >= 0
|x| = -x if x < 0
the cube of a negative value is also negative (but that doesn't really matter here, since we're taking its absolute value)
F(x) is the function that determines the absolute value of the cube of the input.
1.) Evaluate: F(5)
2.) Evaluate: F(-7)
3.) Determine: F(5)⋅F(-7)
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