First, we need to determine the theoretical yield of ethylene. We can do this by setting up a balanced equation for the reaction:
C6H14 + 3C2H4 → 4C2H4
This shows that for every molecule of hexane, we can produce 4 molecules of ethylene. So, we can set up a proportion to find the theoretical yield:
6 moles of hexane : 4 moles of ethylene
x moles of hexane : 1 mole of ethylene
x = (4/6) = 0.67 moles of hexane
Next, we can calculate the mass of ethylene produced from this amount of hexane:
0.67 moles of hexane x (42.5/100) = 0.285 moles of ethylene
Molar mass of ethylene = 28 g/mol
0.285 moles of ethylene x 28 g/mol = 7.98 g
So, 7.98 g of ethylene is the theoretical yield from 0.67 moles of hexane. To produce 481 g of ethylene, we can set up another proportion:
7.98 g of ethylene : 0.67 moles of hexane
481 g of ethylene : x moles of hexane
x = (0.67/7.98) x 481 g ≈ 40.2 g of hexane
Therefore, approximately 40.2 g of hexane must be reacted to produce 481 g of ethylene with a yield of 42.5%.
Ethylene (C 2 H 4 ), an important industrial organic
chemical, can be prepared by heating hexane (C 6 H 14 )
at 8008C:
C6H14 + C2H4
If the yield of ethylene production is 42.5 percent,
what mass of hexane must be reacted to produce 481 g
of ethylene
3 answers
Ethylene (C 2 H 4 ), an important industrial organic
chemical, can be prepared by heating hexane (C 6 H 14 )
at 8008C:
C6H14→C2H4 + other products
If the yield of ethylene production is 42.5 percent,
what mass of hexane must be reacted to produce 481 g
of ethylene
chemical, can be prepared by heating hexane (C 6 H 14 )
at 8008C:
C6H14→C2H4 + other products
If the yield of ethylene production is 42.5 percent,
what mass of hexane must be reacted to produce 481 g
of ethylene
Since there is no balanced chemical equation provided, we cannot determine the exact stoichiometry of the reaction. However, we can use the given yield of 42.5% to calculate the mass of hexane required to produce 481 g of ethylene.
Let x be the mass of hexane required. The 42.5% yield means that 42.5% of the hexane is converted into ethylene, and the rest remains as "other products". Therefore:
0.425x = mass of ethylene produced
We want to find the value of x that gives us a mass of ethylene equal to 481 g:
0.425x = 481 g
Solving for x, we have:
x = 1130 g
Therefore, 1130 g of hexane must be reacted to produce 481 g of ethylene with a yield of 42.5%.
Let x be the mass of hexane required. The 42.5% yield means that 42.5% of the hexane is converted into ethylene, and the rest remains as "other products". Therefore:
0.425x = mass of ethylene produced
We want to find the value of x that gives us a mass of ethylene equal to 481 g:
0.425x = 481 g
Solving for x, we have:
x = 1130 g
Therefore, 1130 g of hexane must be reacted to produce 481 g of ethylene with a yield of 42.5%.
1 answer