Equation: 4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)

Question

question: What volume of NH3 is needed to react with 71.6 liters of oxygen?

Answer 1

Use the coefficients to convert L oxygen to L NH3.
71.6 L O2 x (4 moles NH3/5 moles O2) = 71.6 x (4/5) = ??

Answer 2

thanks Dr. Bob