4NH3(g) + 5O2(g) → 4NO (g) + 6H2O(g)
Using the above equation, at STP, when 0.675 L of ammonia burns, what volume of water vapor will be formed?
1 answer
H2O:NH3 = 6:4
Using the above equation, at STP, when 0.675 L of ammonia burns, what volume of water vapor will be formed?
1 answer