energy required for ionisation of 0.02 gram atom of magnesium is x Kj .the amount of energy required to ionise 1 atom of magnesium is
4 answers
x kJ/(6.02E23*0.02) = ?
Since I. E. is same, therefore energy required is XkJ
Hey there!
Energy required for 0.02 gm of Mg --------->
xkJ
Energy required for 1gm of Mg ------------->
x/0.02 kJ
We know that, 1 atom = 6.022 × 10²³ gm
(6.022 × 10 ²³ is known as Avagadro Number and is donated by NA)
So,
Energy required for NA -----------> x/0.02*NA kJ
Now, let's convert kJ into J
We know that, 1kJ = 1000 J
So, the final answer is,
x*10³/0.02NA J
Hope you got it!
Have a good day!
Energy required for 0.02 gm of Mg --------->
xkJ
Energy required for 1gm of Mg ------------->
x/0.02 kJ
We know that, 1 atom = 6.022 × 10²³ gm
(6.022 × 10 ²³ is known as Avagadro Number and is donated by NA)
So,
Energy required for NA -----------> x/0.02*NA kJ
Now, let's convert kJ into J
We know that, 1kJ = 1000 J
So, the final answer is,
x*10³/0.02NA J
Hope you got it!
Have a good day!
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1 answer