In a parallelogram, opposite sides are equal in length. Therefore, we can set up the following equations based on the sides of quadrilateral ABCD:
- \( AB = CD \)
- \( BC = AD \)
For sides given:
- \( AB = 40y \)
- \( BC = 4 + 3x \)
- \( CD = 8y + 32 \)
- \( AD = 9x - 20 \)
Using the first equation, we can set \( AB \) equal to \( CD \):
\[ 40y = 8y + 32 \]
Now, solve for \( y \):
\[ 40y - 8y = 32 \ 32y = 32 \ y = 1 \]
Next, we use the second equation. Set \( BC \) equal to \( AD \):
\[ 4 + 3x = 9x - 20 \]
Now, solve for \( x \):
\[ 4 + 20 = 9x - 3x \ 24 = 6x \ x = 4 \]
Thus, the values we found are \( x = 4 \) and \( y = 1 \).
So the correct response is:
x = 4 and y = 1