Earth is a spherical body, of radius 6,376 km, which completes a full rotation about its axis in 24.0 h. how long (in hours) should the day on Earth be so that a person at the equator is able to float freely above the ground?

Answer 1

acceleration due to gravity=9.8m/s^2
centripetal acceleration=w^2 *r (r is given, w=2PI/(T*3600) rad/s
set them equal, solve for Period T.

9.8=4PI^2/(T^2*3600^2)

T=2PI/3600 sqrt(1/9.8) check my math, T is in hours.

Answer 2

what is PI?