You will have to draw a sketch first, then note that the two magnetic field will be opposing in a large degree. So break up each magnetic field into a horizontal component (which the add in the same direction), and a vertical, which oppose and cancel. Then compute the sum in each direction.
There is an easier way, once you realize what is happening. Both fields are equal in magnitude, so it is you have to compute only one field in the horizontal component, and double it.
Ul I/2PIr * sinTheta * 2
and Theta = arcCos12/14
Draw the sketch.
Each of two long straight parallel wires separated by a distance of 24.0 cm carries a current of 5.00 A
in the same direction. What is the magnitude of the resulting magnetic field at a point that is 14.0 cm
from each wire?
I have tried (U0I/2pir)2 as well as U0I/4pia(cos(theta) -cos(theta2)) Where theta 1 is approx 30 and theta 2 is approx 150. And a series of other variations which never yield close to the given answers. I would like to know which equation I am supposed to use. Been working on this since for 5 days now.
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