e^(x-y)=-x+C where y(2)=2

Question

so I found C=3?

y=_____________

so I thought it would be y=-ln(-x+3)-x but that is wrong please help!

Answer 1

since y(2) = 2,

e^(2-2) = -2+c
1 = -2+c
3 = c
So far, so good.

e^(x-y) = -x+3
x-y = ln(-x+3)
y = x-ln(-x+3)

Somehow you got an extra "-" sign in there

Answer 2

Thank you!