since y(2) = 2,
e^(2-2) = -2+c
1 = -2+c
3 = c
So far, so good.
e^(x-y) = -x+3
x-y = ln(-x+3)
y = x-ln(-x+3)
Somehow you got an extra "-" sign in there
e^(x-y)=-x+C where y(2)=2
so I found C=3?
y=_____________
so I thought it would be y=-ln(-x+3)-x but that is wrong please help!
2 answers
Thank you!