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During an adiabatic process, the temperature of 6.50 moles of a monatomic ideal gas drops from 525 °C to 169 °C. What is the work done?

Here is my work, is it correct?

T1 = 525+273 = 798 K

T2 = 169 + 273 = 442 K

work done = R[T2-T1]/1-gamma = 8.314[525 - 798]/(1-1.67) = - 4417.58 J

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