During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by s(t) = -16t^2 + 70t + 3, where t is the time in seconds. What is the time when the softball will be 50 feet above the ground?

Answer 1

To find the time when the softball will be 50 feet above the ground, we need to set the equation s(t) = -16t^2 + 70t + 3 equal to 50 and solve for t.

So, we have:

-16t^2 + 70t + 3 = 50

Rearranging the equation, we get:

-16t^2 + 70t + 3 - 50 = 0

Bringing like terms together, we have:

-16t^2 + 70t - 47 = 0

Now, we can solve the quadratic equation.