To find the time when the softball will be 50 feet above the ground, we need to set the equation s(t) = -16t^2 + 70t + 3 equal to 50 and solve for t.
So, we have:
-16t^2 + 70t + 3 = 50
Rearranging the equation, we get:
-16t^2 + 70t + 3 - 50 = 0
Bringing like terms together, we have:
-16t^2 + 70t - 47 = 0
Now, we can solve the quadratic equation.
During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by s(t) = -16t^2 + 70t + 3, where t is the time in seconds. What is the time when the softball will be 50 feet above the ground?
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