To find the time when the softball will be 50 feet above the ground, we need to set the equation s(t) = 50 and solve for t.
-16t^2 + 70t + 3 = 50
-16t^2 + 70t - 47 = 0
We can solve this quadratic equation using the quadratic formula:
t = (-b ± √(b^2 - 4ac))/(2a)
Plugging in the values, we get:
t = (-70 ± √(70^2 - 4(-16)(-47)))/(2(-16))
Simplifying further:
t = (-70 ± √(4900 - 3016))/(-32)
t = (-70 ± √1884)/(-32)
Calculating the square root:
t = (-70 ± 43.42)/(-32)
Simplifying further:
t = (70 + 43.42)/32 OR t = (70 - 43.42)/32
t = 113.42/32 OR t = 26.58/32
t ≈ 3.55 seconds OR t ≈ 0.83 seconds
The closest answer to the time when the softball will be 50 feet above the ground is 0.83 seconds or 3.55 seconds.
Whats the right answer
During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by s left-parenthesis t right-parenthesis equals negative 16 t squared plus 70 t plus 3, where t is time in seconds and t greater than or equal to 0. Which is closest to the time when the softball will be 50 feet above the ground?
(1 point)
Responses
0.66 seconds
0.66 seconds
5.03 seconds
5.03 seconds
0.83 seconds or 3.55 seconds
0.83 seconds or 3.55 seconds
0.66 seconds or 5.03 seconds
1 answer
1 answer