F=Ma
F=M(∆V/t)
∆V=Vf-Vi=-15m/s-0m/s=-15m/s
t=3s
m=0.060 kg
Plug and chug
F=(0.060 kg)[(-15m/s)/3s]
During a rain storm, rain comes straight down with velocity Vi =-15 m/s and hits the roof of a car perpendicularly. The mass of the rain per second that strikes the roof is 0.060 kg every second. Assuming that the rain comes to rest upon strikingthe car ( Vf = 0 m/s), find the average force exerted by rain on the roof during a 3 second time interval.
3 answers
The time interval doesn't matter.
F = (0.060 kg/s)(15 m/s) = 0.90 N
F = (0.060 kg/s)(15 m/s) = 0.90 N
I think that it would: F=ma, and F=mdV
1 answer