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During a game of tug-of-war, two students are pulling on a rope. One student pulls to the left with a force of 35 N, while anot...Asked by follow my ig bigmeltoogrimy13
                During a game of tug-of-war, two students are pulling on a rope. One student pulls to the left with a force of 35 N, while another student pulls to the right with a force of 35
N. What is the net force being applied to the rope, and in which direction will the rope move? (1 point)
O 70 N; the rope will stay stationary O ON; the rope will stay stationary
• 35 N; the rope will move to the right
O 17.5 N; the rope will move up
            
        N. What is the net force being applied to the rope, and in which direction will the rope move? (1 point)
O 70 N; the rope will stay stationary O ON; the rope will stay stationary
• 35 N; the rope will move to the right
O 17.5 N; the rope will move up
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                    Answered by
            GPT-4o mini
            
    In this scenario, both students are pulling on the rope with an equal force of 35 N in opposite directions. 
To find the net force, we add the forces considering their directions:
- One student pulls to the left with a force of 35 N (we can consider this as -35 N).
- The other student pulls to the right with a force of 35 N (we can consider this as +35 N).
Calculating the net force:
\[
\text{Net force} = 35 \text{ N} (right) + (-35 \text{ N}) (left) = 0 \text{ N}
\]
Since the net force is 0 N, this means there is no unbalanced force acting on the rope.
Therefore, the rope will stay stationary.
The correct answer is:
- **0 N; the rope will stay stationary.**
    
To find the net force, we add the forces considering their directions:
- One student pulls to the left with a force of 35 N (we can consider this as -35 N).
- The other student pulls to the right with a force of 35 N (we can consider this as +35 N).
Calculating the net force:
\[
\text{Net force} = 35 \text{ N} (right) + (-35 \text{ N}) (left) = 0 \text{ N}
\]
Since the net force is 0 N, this means there is no unbalanced force acting on the rope.
Therefore, the rope will stay stationary.
The correct answer is:
- **0 N; the rope will stay stationary.**
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