Draw the Lewis structure for N2H2, a neutral molecule.

Answer 1

N2H2.
N has 5 + 5 = 10 electrons
H has 1 + 1 = 2 electrons.
Total of 12 electrons.
I would distribute the 12 as follows:
H:N::N:H which accounts for 8. Place a pair of unshared electron on the first N and a pair of unshared electrons on the second N. That will add 4 more electrons to make the 12. Note that there are two electrons for each H and 8 electrons for each N which satisfies the rule of 8 (and 2 for H). Note also that H:N:::N:H only accounts for 10 of the electrons and if an extra pair of electrons is added to one of the N atoms, the rule of 8 is not followed.