draw a valid lewis structure for each molecule. NC13 lewis dot structure

Answer 1

To draw the Lewis dot structure for NC13, we first need to determine the total number of valence electrons in the molecule.

N (Nitrogen) has 5 valence electrons, and each Cl (Chlorine) has 7 valence electrons.

So, the total number of valence electrons in NC13 is:
1(N) + 1(C) + 3(Cl) = 1(5) + 1(4) + 3(7) = 5 + 4 + 21 = 30 electrons.

Now, let's arrange these electrons around the atoms to form bonds and fulfill the octet rule.

We start by connecting Nitrogen (N) to Carbon (C) using a single bond, which uses 2 electrons:

N - C

Then, we connect each Chlorine (Cl) atom to Carbon (C) using a single bond, which uses 2 electrons for each bond:

N - C - Cl
|
Cl
|
Cl

After connecting the atoms with single bonds, we distribute the remaining electrons to complete the octet of each atom.

Starting with Carbon (C) which already has 2 electrons, we add 6 more electrons:

N - C - Cl
|
Cl
|
Cl
|
(6 e-)

Next, we add 3 more electrons to complete the octet of the Nitrogen (N) atom:

N (6e-) - C - Cl
|
Cl
|
Cl
|
(3 e-)

Finally, we add 7 electrons to complete the octet of each Chlorine (Cl) atom:

N (6e-) - C - Cl
|
Cl (8e-)
|
Cl (8e-)
|
(3 e-)

This configuration fulfills the octet rule, and all the 30 valence electrons have been used.

Therefore, the valid Lewis dot structure for NC13 is:

N
|
Cl - C - Cl
|
Cl